## Java Program to Reverse a Number

Here you will get java program to reverse a number with while loop and recursion.

When we divide a number with 10 then the remainder is the last digit of number and quotient is the number without last digit. **/** operator is used find quotient and **%** operator is used to find remainder. We use this concept to reverse the number.

**Example:**

Initially n = 123, reverse = 0

**Step 1:**

remainder = n % 10 = 123 % 10 = 3

reverse = (reverse * 10) + remainder = (0 * 10) + 3 = 3

n = n / 10 = 123 / 10 = 12

**Step 2:**

remainder = n % 10 = 12 % 10 = 2

reverse = (reverse * 10) + remainder = (3 * 10) + 2 = 32

n = n / 10 = 12 / 10 = 1

**Step 3:**

remainder = n % 10 = 1 % 10 = 1

reverse = (reverse * 10) + remainder = (32 * 10) + 1 = 321

n = n / 10 = 1 / 10 = 0

We repeat above steps until n becomes 0. Finally reverse of number is obtained.

## Java Program to Reverse a Number

**Using While Loop**

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import java.util.Scanner; public class JavaReverseNumber { public static void main(String...s){ int n,reverse = 0,remainder; Scanner sc = new Scanner(System.in); System.out.println("Enter a number:"); n = sc.nextInt(); while(n!=0){ remainder = n%10; reverse = (reverse * 10) + remainder; n = n/10; } System.out.println("Reverse of number is " + reverse); } } |

**Output**

*Enter a number:*

*1159*

*Reverse of number is 9511*

**Using Recursion**

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import java.util.Scanner; public class JavaReverseNumber { public static void main(String...s){ int n,reverse = 0; Scanner sc = new Scanner(System.in); System.out.println("Enter a number:"); n = sc.nextInt(); reverse = reverseNumber(n, reverse); System.out.println("Reverse of number is " + reverse); } static int reverseNumber(int n, int reverse){ int remainder; if(n == 0){ return reverse; } remainder = n%10; reverse = (reverse * 10) + remainder; return reverseNumber(n/10, reverse); } } |

**Output**

*Enter a number:*

*8764*

*Reverse of number is 4678*

Comment below if you have doubts or found anything incorrect in above java program to reverse a number.